Rd sharma class 10 solutions chapter 9 exercise 9.5. R D Sharma Class 10 Solutions 2019-06-16

Rd sharma class 10 solutions chapter 9 exercise 9.5 Rating: 8,5/10 1053 reviews

R D Sharma Class 9 Solutions

rd sharma class 10 solutions chapter 9 exercise 9.5

Solution 5 : Answer : The given expression to be factorized is Rearrange the given expression as Take common from the first two terms and -1 from the last two terms. So, the required factorization of is. Then we get This can be written in the following form Recall the formula for the cube of the sum of two numbers Using the above formula, we have We cannot further factorize the expression. We cannot further factorize the expression. Question: 38 In an A.

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R D Sharma Class 10 Solutions

rd sharma class 10 solutions chapter 9 exercise 9.5

So, the required factorization is ofis. So, here we use the following formula for the sum of n terms of an A. If 1 is added to each term of this A. That is Finally, take commonfrom the two terms. So, here we use the following formula for the sum of n terms of an A. Solution: In the given problem, let us take the first term as a and the common difference as d. That is So, the correct choice is d.

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R D Sharma Class 9 Solutions

rd sharma class 10 solutions chapter 9 exercise 9.5

The sum of all these terms is 442. Then the expression becomes Exercise 5. Also, all these terms will form an A. P is and the common difference is Exercise 9. So, the required factorization is.

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R.D. Sharma Class 10 Solutions

rd sharma class 10 solutions chapter 9 exercise 9.5

So, the required factorization ofis. So, the required factorization of is. Then the given expression can be rewritten as Recall the formula for difference of two cubes Using the above formula, the expression becomes Note that both, b is positive and unequal. Also, all these terms will form an A. Solution: In the given problem, we need to find the sum of the n terms of the given A.

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R.D. Sharma Class 10 Solutions

rd sharma class 10 solutions chapter 9 exercise 9.5

Solution 12 : Answer : The given equation is Recall the formula Using the above formula, we have , provided. Solution 5 : Answer : The given expression to be factorized is This can be written in the form Recall the formula Using the above formula, we have We cannot further factorize the expression. Then the expression becomes So, the correct choice is b. Find the n th term of this A. Solution 18 : Answer : The given expression to be factorized is This can be written as Recall the formula for difference of two cubes Using the above formula, we have We cannot further factorize the expression. So, the required factorization of is.

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RD Sharma Class 9 Solutions

rd sharma class 10 solutions chapter 9 exercise 9.5

Then we have Finally take commonfrom the above expression, We cannot further factorize the expression. So, to find the first term we use, we get, Similarly, we find the other four terms, Second term , Third term, Fourth term, Fifth term, Therefore, the first five terms of the given A. Solution 4 : Answer : The given expression to be factorized is This can be written in the form Take common from the last two terms. Then we get, We cannot further factorize the expression. So, the required factorization is of is.

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RD SHARMA CLASS

rd sharma class 10 solutions chapter 9 exercise 9.5

Then we get This can be written in the following form Recall the formula for the cube of the difference of two numbers Using the above formula, we have We cannot further factorize the expression. Hence write the 20 th term. We, at DronStudy, understand that sometimes just reading the solutions is not enough to fully understand the concepts involved. So, the required factorization is of is. So, the required factorization is of is. So, the required factorization of is. Using the above formula, the value of the given expression is.

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RD Sharma Class 10 Maths Solutions Chapter 9

rd sharma class 10 solutions chapter 9 exercise 9.5

Dronstudy makes all these solutions easily available for free in a. Common difference of the A. . Let us take the first term as a. Solution 2 : Answer : The given expression to be factorized is This can be written in the form Take common from the last two terms,.

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R D Sharma Class 10 Solutions

rd sharma class 10 solutions chapter 9 exercise 9.5

So, to find the first term we use, we get, Similarly, we find the other four terms, Second term , Third term, Fourth term, Fifth term, Therefore, the first five terms for the given sequence are. Solution 8 : Answer : The given expression to be factorized is This can be written in the form Take common from the last two terms,. This makes it extremely easy to navigate and select the specific topics for which you need the solutions. So, the required factorization of is. So, we know that the first multiple of 7 after 50 is 56 and the last multiple of 7 before 500 is 497. Similarly find the third, the tenth and the n­ th term.

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RD Sharma Class 10 Solutions Chapter 9

rd sharma class 10 solutions chapter 9 exercise 9.5

Then we get This can be written in the following form Recall the formula for the cube of the difference of two numbers Using the above formula, we have We cannot further factorize the expression. We cannot further factorize the expression. Mathematics of one of the most important subjects as it forms the basis for physics and chemistry as well. Solution: In this problem, we need to find the sum of all the multiples of 7 lying between 50 and 500. So, the required factorization is. Then the given expression can be rewritten as Recall the formula for difference of two cubes Using the above formula, the expression becomes Note that both, b is positive and unequal.

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